Question
Download Solution PDFA cook earns ₹8,400 per month. If she spends 60% of it each month, how much will she save (in ₹) by one-fourth of a year?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Monthly income of the cook = ₹8,400
Percentage of income spent = 60%
Time period = One-fourth of a year = 3 months
Formula Used:
Monthly savings = Monthly income × (100% - Percentage spent)
Total savings = Monthly savings × Number of months
Calculation:
Monthly savings = 8,400 × (100% - 60%)
⇒ Monthly savings = 8,400 × 40%
⇒ Monthly savings = 8,400 × (40 / 100)
⇒ Monthly savings = 8,400 × 0.4
⇒ Monthly savings = ₹3,360
Total savings = Monthly savings × Number of months
⇒ Total savings = 3,360 × 3
⇒ Total savings = ₹10,080
The cook will save ₹10,080 in one-fourth of a year.
Last updated on Jul 17, 2025
-> RRB NTPC Under Graduate Exam Date 2025 has been released on the official website of the Railway Recruitment Board.
-> The RRB NTPC Admit Card will be released on its official website for RRB NTPC Under Graduate Exam 2025.
-> UGC NET Result 2025 out @ugcnet.nta.ac.in
-> HSSC CET Admit Card 2025 has been released @hssc.gov.in
-> Candidates who will appear for the RRB NTPC Exam can check their RRB NTPC Time Table 2025 from here.
-> The RRB NTPC 2025 Notification released for a total of 11558 vacancies. A total of 3445 Vacancies have been announced for Undergraduate posts like Commercial Cum Ticket Clerk, Accounts Clerk Cum Typist, Junior Clerk cum Typist & Trains Clerk.
-> A total of 8114 vacancies are announced for Graduate-level posts in the Non-Technical Popular Categories (NTPC) such as Junior Clerk cum Typist, Accounts Clerk cum Typist, Station Master, etc.
-> Prepare for the exam using RRB NTPC Previous Year Papers.
-> Get detailed subject-wise UGC NET Exam Analysis 2025 and UGC NET Question Paper 2025 for shift 1 (25 June) here
->Bihar Police Driver Vacancy 2025 has been released @csbc.bihar.gov.in.