Question
Download Solution PDFA toroidal coil has a magnetic path length of 30 cm and a magnetic field strength of 750 A/m. The coil current is 250 mA. Determine the number of coil turns.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The magnetic field strength is given by:
\(H={Ni\over l}\)
where, H = Magnetic field strength
N = No. of turns
i = Current
l = Magnetic path length
Calculation
Given, l = 30 cm = 0.3 m
H = 750 A/m
i = 250 mA
\(750={N\times 0.25\over 0.3}\)
N = 900 turns
Last updated on Jun 7, 2025
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