A TV set is being sold for Rs. X in Delhi. A dealer went to Chandigarh and bought the TV at 20% discount (from the price of Delhi). He spends Rs. 600 on transport. Thus, he sold the set in Delhi for Rs. X making (100/7) % profit what is the value of X?

Question

Question

This question was previously asked in

RRC Group D Previous Paper 1 (Held On: 17 Sep 2018 Shift 1)

Answer 1

Given :

A TV set selling price in Delhi = Rs. X

The discount is given on TV set in Chandigarh = 20%

Profit % = 100/7% = \(14\frac{2}{7}\)%

Transportation cost = Rs. 600

Formula Used:

Selling price = Cost Price × (100 + P%)/100

Calculation:

CP = 80% of X = 0.8X

According to the question

⇒ X = \(\frac{0.8X + 600 (100 + \frac{100}{7})}{100}\)

⇒ X = \(\frac{0.8X + 600 (\frac{800}{7})}{100}\)

⇒ 100X = \(\frac{(0.8X + 600)(800)}{7}\)

⇒ 700X = (0.8X + 600)(800)

⇒ 700X = 640X + 480000

⇒ 60X = 480000

⇒ X = 8000

∴ The value of X is Rs.8000

⇒ Selling Price of TV in Chandigarh = X – 20% of X = Rs. 0.8X

⇒ Total cost price of TV in Delhi = 0.8X + 600

⇒ Selling Price = Rs. X

⇒ Profit% = {(X – 0.8X – 600)/(0.8X + 600)} × 100

⇒ 100/7 = {(0.2X – 600) / (0.8x + 600)} × 100

⇒ 0.8X + 600 = 1.4X – 4200

⇒ X = 8000