Question
Download Solution PDFAn RLC series circuit has resonance frequency of 170 kHz and quality factor of 25. Find the bandwidth of the circuit.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
For a series RLC circuit, the bandwidth of the circuit is given by:
\(BW={f_o\over QF}\)
where, fo = Resonant frequency
QF = Quality factor
Calculation
Given, fo = 170 kHz
QF = 25
\(BW={170\over 25}\)
BW = 6.8 kHz
Additional Information For a series RLC circuit:
Damping factor, \(\zeta={R\over 2}\sqrt{C\over L}\)
Quality factor, \(QF={1\over R}\sqrt{L\over C}\)
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