Question
Download Solution PDFFind the total current fed at the sending end A, in the given ring distributor ABC_________.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFLet us assume the current flowing from node A is IA.
The impedance between AB and AC is the same, so the current I will be divided equally into 2 parts.
The current going in BC is:
\(I_{BC}={I_A\over 2}-8\angle53.13\)
Applying KCL at node C:
\({I_A\over 2}-8\angle53.13+{I_A\over 2}=12\angle36.86\)
IA = 12 (0.8 + j0.6) + 8 (0.6 + j0.8)
So, IA = (14.4 + j13.6) A
Last updated on Jun 16, 2025
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