Question
Download Solution PDF23.1 सेमी लंबाई का एक चाप, केंद्र पर 18° का कोण अंतरित करता है। वृत्त का क्षेत्रफल कितना है? [ \(π = \frac{22}{7}\) का प्रयोग कीजिए]
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
चाप की लंबाई = 23.1 सेमी
चाप द्वारा केंद्र पर बनाया गया कोण = 18°
प्रयुक्त सूत्र:
चाप की लंबाई = (2 × π × R × θ)/360
वृत्त का क्षेत्रफल = π × R2
जहाँ, R = त्रिज्या
गणना:
चाप की लंबाई = (2 × π × R × θ)/360
⇒ 23.1 = (2 × 22 × R × 18)/(360 × 7)
⇒ 23.1 = (22 × R)/(10 × 7)
⇒ R = (2.1 × 70)/2 = 73.5 सेमी
वृत्त का क्षेत्रफल = π × R2
⇒ (22/7) × 73.5 × 73.5
⇒ 22 × 10.5 × 73.5
⇒ 16978.50 सेमी2
∴ सही उत्तर 16978.50 सेमी2 है।
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