यदि \((x+\frac{1}{x})\) = 5 है, और x > 1 है, तब \((x^8-\frac{1}{x^8} )\) का मान क्या है?

This question was previously asked in
SSC CGL 2023 Tier-I Official Paper (Held On: 18 Jul 2023 Shift 3)
View all SSC CGL Papers >
  1. \(60605\sqrt{21}\)
  2. \(60615\sqrt{21}\)
  3. \(60705\sqrt{21}\)
  4. \(60725\sqrt{21}\)

Answer (Detailed Solution Below)

Option 1 : \(60605\sqrt{21}\)
vigyan-express
Free
PYST 1: SSC CGL - General Awareness (Held On : 20 April 2022 Shift 2)
3.6 Lakh Users
25 Questions 50 Marks 10 Mins

Detailed Solution

Download Solution PDF

दिया गया है:

\((x+\frac{1}{x})\) = 5 और x > 1

गणना:

\((x+\frac{1}{x})\) = 5

इसलिए x2 + 1/x2 = 25 - 2

⇒ 23

पुनः,

x - 1/x = √21

x2 - 1/x2 =5√21

⇒ x4 + 1/x4 = 529 - 2

⇒ 527

x4 - 1/x4 =115√21 

x8 - 1/x8 =( x4 + 1/x4 ) ×(x4 - 1/x4 )

⇒ 115√21 × 527 

= 60605√21

∴ सही विकल्प 1 है।

Latest SSC CGL Updates

Last updated on Jul 7, 2025

-> The SSC CGL Notification 2025 for the Combined Graduate Level Examination has been officially released on the SSC's new portal – www.ssc.gov.in.

-> This year, the Staff Selection Commission (SSC) has announced approximately 14,582 vacancies for various Group B and C posts across government departments.

-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025.

->  Aspirants should visit ssc.gov.in 2025 regularly for updates and ensure timely submission of the CGL exam form.

-> Candidates can refer to the CGL syllabus for a better understanding of the exam structure and pattern.

-> The CGL Eligibility is a bachelor’s degree in any discipline.

-> Candidates selected through the SSC CGL exam will receive an attractive salary. Learn more about the SSC CGL Salary Structure.

-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.

-> Candidates should also use the SSC CGL previous year papers for a good revision. 

More Algebra Questions

Get Free Access Now
Hot Links: teen patti 3a teen patti diya all teen patti master teen patti pro teen patti joy