Question
Download Solution PDFत्रिभुज ABC में, कोण BAC का समद्विभाजक, भुजा BC को D पर काटता है। यदि AB = 10 सेमी, और AC = 14 सेमी है, तो BD : BC का मान क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
AB = 10 सेमी, और AC = 14 सेमी
प्रयुक्त अवधारणा:
त्रिभुज का कोण समद्विभाजक सम्मुख भुजा को त्रिभुज की अन्य दो भुजाओं के समानुपाती दो भागों में विभाजित करता है।
गणना:
अवधारणा के अनुसार,
AB/AC = BD/DC
⇒ 10/14 = BD/DC
⇒ 5/7 = BD/DC
इसलिए, BD : DC = 5 : 7
अब, BC = 5 + 7
⇒ 12
इसलिए, BD : BC = 5 : 12
∴ अभीष्ट उत्तर 5 : 12 है।
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