12 सेमी त्रिज्या वाले एक वृत्त के त्रिज्यखंड का क्षेत्रफल 32 π सेमी2 है। त्रिज्यखंड के संगत चाप की लम्बाई ज्ञात कीजिए।

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SSC CGL 2023 Tier-I Official Paper (Held On: 17 Jul 2023 Shift 4)
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  1. \(\frac{16}{3}\) π सेमी
  2. \(\frac{13}{3}\) π सेमी
  3. \(\frac{10}{3}\) π सेमी
  4. \(\frac{8}{3}\) π सेमी

Answer (Detailed Solution Below)

Option 1 : \(\frac{16}{3}\) π सेमी
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Detailed Solution

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दिया गया है:

वृत्त के एक त्रिज्यखंड का क्षेत्रफल = 32 π सेमी2

वृत्त की त्रिज्या (R) = 12 सेमी

प्रयुक्त सूत्र:

एक त्रिज्यखंड का क्षेत्रफल = (π × R2 × θ)/360

चाप की लम्बाई = (2 × π × R × θ)/360

गणना:

एक त्रिज्यखंड का क्षेत्रफल = (π × R2 × θ)/360

⇒ 32π = (π × (12)2 × θ)/360

⇒ 32 × 360 = (144 × θ)

⇒ θ = (32 × 360)/144

⇒ θ = 80° 

चाप की लम्बाई = (2 × π × R × θ)/360

⇒ (2 × π × 12 × 80)/360

⇒ (16/3) × π

∴ सही उत्तर \(\frac{16}{3}\) π सेमी​ है।

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