निम्नलिखित व्यंजक किसके बराबर है?

cot 85°+ cos 75°

This question was previously asked in
SSC CGL 2023 Tier-I Official Paper (Held On: 20 Jul 2023 Shift 2)
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  1. tan 85°+ sin 75°
  2. tan 5°+ sin 15°
  3. tan 85°- sin 75°
  4. tan 5°- sin 15°

Answer (Detailed Solution Below)

Option 2 : tan 5°+ sin 15°
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Detailed Solution

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प्रयुक्त सूत्र:

sin(90-θ) = cos θ

cot(90-θ) = tan θ

गणना

⇒ cot 85°+ cos 75°

⇒ cot (90 - 5)°+ cos (90 - 15)°

⇒ cot (90 - 5)°+ cos (90 - 15)°

⇒ tan 5°+ sin 15°

उत्तर tan 5°+ sin 15° है

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