Question
Download Solution PDF21 से 50 के बीच सभी अभाज्य संख्याओं के माध्य और माध्यक में कितना अंतर है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFप्रयुक्त सूत्र:
माध्य = प्रेक्षणों का योग/ प्रेक्षणों की संख्या
गणना:
21 से 50 के बीच अभाज्य संख्याएँ निम्नलिखित हैं:
⇒ 23, 29, 31, 37, 41, 43, 47
माध्य = \(\dfrac{23 + 29 + 31 + 37 + 41 + 43 +47}{7}\)
⇒ \(\dfrac{251}{7}\)
कुल संख्याएँ = 7 (विषम संख्या)
इसलिए, माध्यक = [(n + 1)/2]वाँ पद
⇒ [(7 + 1)/2]वाँ पद
⇒ चौथा पद = 37
माध्य और माध्यक के बीच अंतर:
⇒ 37 - \(\dfrac{251}{7}\)
⇒ \(\dfrac{259 - 251}{7}\) = \(\dfrac{8}{7}\)
∴ सही उत्तर विकल्प 2 है।
Last updated on Feb 17, 2025
-> MP Excise Constable 2025 application link has been activated.
-> Eligible candidates can apply from 15th February 2025 to 1st March 2025.
-> The MP Excise Constable recruitment offers 253 vacancies, including 248 direct vacancies and 5 backlog vacancies.
-> The online examination is scheduled to be conducted on 5th July 2025.
-> The selected candidates for the Excise Constable post will get a salary range between Rs. 19,500 to Rs. 62,000.
-> Candidates must go through the MP Excise Constable's previous year's papers to understand the type of questions coming in the examination and make a preparation plan accordingly.