How far will the tip of a 2 cm-long minute hand of a clock move in 45 minutes?

Question

Question

This question was previously asked in

SSC CGL 2022 Tier-I Official Paper (Held On : 02 Dec 2022 Shift 3)

Answer 1

Given:

The minute hand of a watch is 2 cm long.

Formula Used:

Arc length, l = r × θ

l = arc length (in radian)

r = radius

θ = central angle in radian

1° = π^c/180

Calculation:

We know that,

Angle traced by the minute hand in 60 min = (2π)^c

Angle traced by the minute hand in 45 min = [(2π × 45)/60]^c

⇒ (3π/2)^c

⇒ r = 2 cm and θ =

(3π/2)c

⇒ l = r × θ

⇒ l = 2 × (3π/2)c

⇒ l = 3π

∴ The required answer is 3π cm.

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