Question
Download Solution PDFIdentify the state of sand, if the number of blow in the SPT test is more than 50.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Penetration resistance and soil properties on the basis of SPT for cohesionless soils:
| SPT N value | 0 - 4 | 4 - 10 | 10 - 30 | 30 - 50 | > 50 | |
| Compactness | Very Loose | Loose | Medium | Dense | Very Dense | |
| Relative Density (Dr%) | 0 - 15 | 15 - 35 | 35 - 65 | 65 - 85 | 85 - 100 | |
| Angle of Internal Friction (ϕ∘) | < 28 | 28 - 30 | 30 - 36 | 36 - 41 | > 41 | |
| Moist Unit Weight | kN/m3 | < 14.7 | 14.9 - 19.6 | 17.3 - 20.4 | 17.3 - 22.0 | > 20.4 |
| Submerged Unit Weight | kN/m3 | < 9.4 | 8.6 - 10.2 | 9.4 - 11.0 | 10.5 - 13.4 | > 11.8 |
If the number of below (N) in the SPT test for cohesionless soil (sand) is more than 50, then the cohesionless soil (sand) is very dense.
Additional Information
Penetration resistance and soil properties on the basis of SPT for cohesive soils:
| SPT N value | 0 - 2 | 2 - 4 | 4 - 8 | 8 - 16 | 16 - 32 | > 32 | |
| Compactness | Very Soft | Soft | Medium | Stiff | Very stiff | Hard | |
| Unconfined Compression Pressure (kN/m2) | 0 - 25 | 25 - 50 | 50 - 100 | 100 - 200 | 200 - 400 | > 400 | |
| Saturated Unit weight | < 15.7 | 15.7 - 18.8 | 17.3 - 19.6 | 18.1 - 20.4 | 18.8 - 20.0 | > 20.4 | |
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