If a 10 kg body is moving with a speed of 15 m/s, is acted upon by a retarding force of 50 N, then how long will it take for the body to come to a stop?

Question

Question

Answer 1

CONCEPT:

Force: The interaction which after applying on a body changes or try to change the state of rest or state of motion of the body is called force.

Force (F) = Mass (m) × acceleration (a)

Retardation: The force acting in the opposite direction to the motion of a body is called the retarding force. This force produces negative acceleration for the body which is called retardation or deacceleration.

Retardation (a) = Force/Mass

The equation of motion is given below:

V = u + a t

Where V is final velocity, u is initial velocity, a is acceleration and t is time

CALCULATION:

Given that:

Mass (m) = 10 kg, Initial velocity (u) = 15 m/s

Force (F) = - 50 N

Acceleration (a) = F/m = - 50/10 = - 5 m/s²

Final velocity (V) = 0 m/s

V = u + a t

0 = 15 - 5 × t

So t = 15/5 = 3 sec