If a current of 2 A flowing through one coil produces flux linkage of 5 Wb-turn in the other coil, then what will be the mutual inductance between the two coils?  

The correct option is 3

Concept:

The mutual inductance (M) between two coils can be defined by the formula:

M = Φ/I

where Φ is the flux linkage (in Weber-turns, Wb-t) and I is the current (in Amperes, A). This formula is derived from the principle that the flux linkage is directly proportional to the current flowing and the proportionality constant is the mutual inductance.

Here, we have a current I of 2A and a flux linkage Φ of 5 Wb-turn. Substituting these values into the formula, we get:

M = Φ/I = 5 Wb-t / 2 A M = 2.5 H

So, the mutual inductance between the two coils will be:

2.5 H