If sin x = \(\frac{3}{10}\), then what is the value of tan x + cot x = ?

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SSC CGL 2023 Tier-I Official Paper (Held On: 20 Jul 2023 Shift 1)
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  1. \(\frac{100}{3 \sqrt{91}} \)
  2. \( \frac{100}{2 \sqrt{83}} \)
  3. \(\frac{100}{7 \sqrt{95}} \)
  4. \( \frac{100}{3 \sqrt{85}}\)

Answer (Detailed Solution Below)

Option 1 : \(\frac{100}{3 \sqrt{91}} \)
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Detailed Solution

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Given:-

sin x = (3/10)

Formula used:- 

1 + tan2x = sec2

secx = 1/cosx 

tan x = sin x/cos x

Calculation:- 

⇒ tanx + cotx

tanx + 1/tanx  

⇒ (1 + tan2x )/tanx 

⇒ sec
2x /tanx  

⇒ 1/sinx cosx  [cosx = (√100 - 9)/10]

⇒ 1/(3/10)(√91/10) = 100/3√91 

∴ The required answer is 100/3√ 91.
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