If \((x - \frac{1}{x})\)= √6, and x > 1, what is the value of \((x^8 - \frac{1}{x^8})\)?

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SSC CGL 2023 Tier-I Official Paper (Held On: 17 Jul 2023 Shift 2)
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  1. 1024√15
  2. 992√15
  3. 998√15
  4. 1012√15

Answer (Detailed Solution Below)

Option 2 : 992√15
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Detailed Solution

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Given:

x - (1/x) = √6

Formula used:

x8 - (1/x8) = {x4 + (1/x4)} × {x2 + (1/x2)} × {x + (1/x)} × {x - (1/x)}

If x - (1/x) = a, then x + (1/x) = √(a2 + 4)

Calculation:

x - (1/x) = √6

x2 + (1/x2) = (√6)2 + 2 = 8

Square both sides:

x4 + (1/x4) = (8)2 - 2 = 62

Using, If x - (1/x) = a, then x + (1/x) = √{(√a)2 + 4} .

x + (1/x) = √{(√6)2 + 4} = √10

Substituting the values, we get

x8 - (1/x8) = {x4 + (1/x4)} × {x2 + (1/x2)} × {x + (1/x)} × {x - (1/x)}

⇒ 62 × 8 × √10 × √6 = 496 × 2 × √15 = 992√15

∴ The correct answer is 992√15.  

 Shortcut Trick

If a - 1/a = m,

• Then a2 +1/a2 = m+ 2

• Then a4 + 1/a4 = m+ 4m+ 2

if a2 +1/a2 = m , then a +1/a = √(m+2) 

⇒ x - 1/x =√6

⇒ x2+1/x2 = (√6)2 +2 = 8

⇒ x +1/x = √10

⇒ x4+ 1/x4 = (√6)4+4(√6)2 +2 = 36+24+2 = 62 

⇒ x8 - (1/x8) = {x4 + (1/x4)} × {x2 + (1/x2)} × {x + (1/x)} × {x - (1/x)}

⇒ 62 × 8 × √10 × √6 = 496 × 2 × √15

992√15

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