In an induction motor, the relationship between gross mechanical power developed and rotor input is _______.

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  1. Gross mechanical power developed = (2 - S) × Rotor input
  2. Gross mechanical power developed = S × Rotor input
  3. Gross mechanical power developed = (1/S) × Rotor input
  4. Gross mechanical power developed = (1 - S) × Rotor input

Answer (Detailed Solution Below)

Option 4 : Gross mechanical power developed = (1 - S) × Rotor input
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Gross mechanical power developed = (1 - S) × Rotor input

Concept:

Power flow in the Induction motor is as shown below.

The relation between the rotor air gap power, rotor copper losses and gross mechanical power output is,

\(\Rightarrow {{P}_{in}}:{{P}_{cu}}:{{P}_{g}}=\frac{1}{s}:1:\left( \frac{1-s}{s} \right)=1:s:\left( 1-s \right)\)

where 

s is the slip

Pin  is power developed in the motor

pg  is the air gap power of the motor

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