Question
Download Solution PDFഒരു സാധാരണ ബഹുഭുജത്തിന്റെ ഓരോ ആന്തരിക കോണും 135° ആണെങ്കിൽ, ബഹുഭുജത്തിന്റെ വികർണ്ണങ്ങളുടെ എണ്ണം കണ്ടെത്തുക.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFഒരു സാധാരണ ബഹുഭുജത്തിന്റെ ഓരോ ആന്തരിക കോണും 135 ആണ്,
⇒ ബാഹ്യ കോൺ = 180° - ആന്തരിക കോൺ = 45°
⇒ ബഹുഭുജത്തിന്റെ വശങ്ങളുടെ എണ്ണം = 360°/ ബാഹ്യ കോൺ = 8
∴ വികർണ്ണങ്ങളുടെ എണ്ണം = n(n - 3)/2 = 8 × (8 - 3)/2 = 20, ഇവിടെ n എന്നത് ഒരു ബഹുഭുജത്തിന്റെ വശങ്ങളുടെ എണ്ണമാണ്.Last updated on Jun 2, 2025
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