Question
Download Solution PDF16, 32, 64, 128,...... मालिकेतील पहिल्या 10 संख्यांची बेरीज किती आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेले आहे:
भूमितीय श्रेढी असलेले पहिले पद 'a' = 16 आणि समान गुणोत्तर 'r' = 2
वापरलेली संकल्पना:
या प्रकारच्या प्रश्नामध्ये, जेथे 'r' > 1, नंतर G.P च्या n पदांची बेरीज = Sn
\( = \frac{{a\left( {{r^n} - 1} \right)}}{{r - 1}}\)
वापरलेले सूत्र:
\({S_n} = \frac{{a\left( {{r^n} - 1} \right)}}{{r - 1}}\)
n = 10
गणना:
दिलेल्या मालिकेचा विचार करून
16, 32, 64, 128, ......
\({S_{10}} = \frac{{16\left( {{2^{10}} - 1} \right)}}{{2 - 1}}\)
⇒ S10 = 16 × 1023 = 16368
∴ दिलेल्या मालिकेतील पहिल्या 10 पदांची बेरीज 16368 आहे
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