दिलेले समीकरण योग्य करण्यासाठी कोणत्या दोन चिन्हांची अदलाबदल करावी?

3 × 12 - 6 ÷ 2 + 12 = 16

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SSC CGL 2023 Tier-I Official Paper (Held On: 25 Jul 2023 Shift 1)
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  1. ÷ आणि +
  2. × आणि ÷
  3. - आणि ÷
  4. - आणि +

Answer (Detailed Solution Below)

Option 3 : - आणि ÷
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दिलेले विधान : 3 × 12 - 6 ÷ 2 + 12 = 16

प्रश्नानुसार , चिन्हे बदलल्यानंतर :

तर,

  • पर्याय - (1): ÷ आणि +

3 × 12 - 6 ÷ 2 + 12 = 16 ⇒ 3 × 12 - 6 + 2 ÷ 12 = 16

3 × 12 - 6 + 0.16 = 16

36 + 0.16 - 6 = 16

36.16 - 6 = 16

30.16 ≠ 16 (डाव्या हाताची बाजू ≠ उजव्या हाताची बाजू)

  • पर्याय - (2): × आणि ÷

3 × 12 - 6 ÷ 2 + 12 = 16 ⇒ 3 ÷ 12 - 6 × 2 + 12 = 16

0.25 - 6 × 2 + 12 = 16

0.25 +12 - 12 = 16

12.25 - 12 = 16

0.25 ≠ 16 (डाव्या हाताची बाजू ≠ उजव्या हाताची बाजू)

  • पर्याय - (3): - आणि ÷

3 × 12 - 6 ÷ 2 + 12 = 16 ⇒ 3 × 12 ÷ 6 - 2 + 12 = 16

3 × 2 - 2 + 12 = 16

6 + 12 - 2 = 16

18 - 2 = 16

16 = 16 (डाव्या हाताची बाजू = उजव्या हाताची बाजू)

  • पर्याय - (4): - आणि +

3 × 12 - 6 ÷ 2 + 12 = 16 3 × 12 + 6 ÷ 2 - 12 = 16

3 × 12 + 3 - 12 = 16

36 + 3 - 12 = 16

39 - 12 = 16

27 ≠ 16 (डाव्या हाताची बाजू ≠ उजव्या हाताची बाजू)

म्हणून, "पर्याय - (3)" हे योग्य उत्तर आहे.
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