Simplify the following.

\(\frac{\sin^3 α + \cos^3 α}{\sin α + \cos α}\)

This question was previously asked in
SSC CGL 2023 Tier-I Official Paper (Held On: 14 Jul 2023 Shift 4)
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  1. 1 + sin α cos α
  2. tan α
  3. 1 - sin α cos α
  4. sec α

Answer (Detailed Solution Below)

Option 3 : 1 - sin α cos α
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Detailed Solution

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Given

\(\frac{\sin^3 α + \cos^3 α}{\sin α + \cos α}\)

Formula Used:

a3 + b3 = (a + b) (a2 + b2 - ab)

sin2θ + cos2θ = 1

Calculation:

\(\frac{\sin^3 α + \cos^3 α}{\sin α + \cos α}\) = [(sin α + cos α) (sin2α + cos2α - sinα cosα)]/(sin α + cos α)

1 - sin α cos α

The value is 1 - sin α cos α.

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