Question
Download Solution PDFఅర్ధగోళం యొక్క వ్యాసార్థం 21 సెం.మీ. అయిన ఘనపరిమాణం (సెం.మీ3లో) ఎంత?
(π = 22/7 ఉపయోగించండి)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఇచ్చిన సమాచారం:
అర్ధగోళం వ్యాసార్థం (r)= 21 సెం.మీ
పద్ధతి లేదా సూత్రం:
అర్ధగోళం ఘనపరిమాణం = 2/3πr3
సాధన:
ఇచ్చిన విలువల్ని సూత్రంలో ప్రతిక్షేపించగా
⇒ ఘనపరిమాణం = 2/3 × 22/7 × 213 = 19404 సెం.మీ3
కావున, అర్థగోళం యొక్క ఘనపరిమాణం 19404 సెం.మీ3.
Last updated on Jun 30, 2025
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