Question
Download Solution PDFThe constant load current for a 230 V single phase energy metre is 20 A at unity power factor. If the meter disc makes 2300 revolutions for 2 hours the meter constant will be ______.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The meter constant of a 1ϕ energy meter is given by:
\(Meter \space constant\space = {No. \space of \space revolutions \space in \space 1 \space hr\over No. \space of \space kW \space in \space 1 \space hr}\)
Calculation
Given, V = 230 volt
I = 20 A
cos ϕ = 1
P = VI cos ϕ
P = 230 × 20 × 1 = 4.6 kW
No. of revolutions in 1 hr = 2300/2 = 1150
\(Meter \space constant\space = {1150 \over 4.6}\)
Meter constant = 250 revolutions / kWh
Last updated on Jun 16, 2025
-> SSC JE Electrical 2025 Notification will be released on June 30 for the post of Junior Engineer Electrical/ Electrical & Mechanical.
-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.
-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31.
-> Candidates with a degree/diploma in engineering are eligible for this post.
-> The selection process includes Paper I and Paper II online exams, followed by document verification.
-> Prepare for the exam using SSC JE EE Previous Year Papers.