The diagonal of the square is 8√2 cm. Find the diagonal of another square whose area is triple that of the first square.

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SSC CGL 2022 Tier-I Official Paper (Held On : 06 Dec 2022 Shift 4)
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  1. \(8\sqrt 5 \) cm
  2. \(8\sqrt 3 \) cm
  3. \(8\sqrt 2 \) cm
  4. \(8\sqrt 6 \) cm

Answer (Detailed Solution Below)

Option 4 : \(8\sqrt 6 \) cm
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Detailed Solution

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Concept Used:

Diagonal of square = √2 a

Calculations:

Diagonal of square = √2 a

So, √2 a = 8√2

⇒ a = 8

⇒  a² = 64 cm²

So, the area if another square = 3(64) = 192

So, it's diagonal= √2 a = √2 × √192 = 8√6 cm

Hence, The Required value is 8√6 cm

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