The specific volume of a wet steam at 1600°C, 80% quality, v_f = 0.011 m³/kg and v_g = 0.3071 m³/kg is:

Explanation:

Concept:

The specific volume of steam is given by

v = v_f + xv_fg

v = vf + x(v_g - v_f)

Where v is the volume at any point in the wet region, v_f is the volume at the saturated liquid, v_g is the volume at saturated vapor, and x is the quality of steam.

If the steam lies within the vapor dome (saturated liquid-vapor region) then it is called wet steam.

Calculation:

Given:

x = 80 % = 0.8, vf = 0.011 m3/kg and vg = 0.3071 m3/kg.

v = vf + x (vg - vf)

v = 0.011 + 0.8 (0.3071 - 0.011)

v = 0.248

v = 0.25 m3/kg. 

Additional Information

Enthalpy in wet region is calculated by

h = h_f + xh_fg

h = hf  + x( h_g - h_f)    

Where h is enthalpy at any point in the wet region, h f is enthalpy at the saturated liquid, hg is enthalpy at saturated vapor and x is the quality of steam.

Entropy in wet region is calculated by

s = s_f + xs_fg

s = s_f + x(s_g - s_f)

Where s is entropy at any point in the wet region, s f is entropy at the saturated liquid, s_g is entropy at saturated vapor and x is quality of steam.