The sum of the radius of the base and the height of a cylinder is 42 m. If the total surface area of the cylinder is 6336 m², find the curved surface area of the cylinder correct to two places of decimals (use π = \(\frac{22}{7}\)).

Question

Question

This question was previously asked in

SSC CHSL Exam 2023 Tier-I Official Paper (Held On: 02 Aug, 2023 Shift 4)

Answer 1

Given:

The radius + height = 42 m.

The total surface area = 6336 m2,

Concept used:

The total surface area of the cylinder = curved surface area of the cylinder + area of the base

Formula used:

The curved surface area = 2πrh (r= radius and h = height)

Calculation:

As per the question,

r + h = 42

Again,

2πr (r + h) = 6336

⇒ 2πr × 42 = 6336

⇒ r = 6336 / 264

⇒ r = 24

Then h = 42 - 24

⇒ 18m

The curved surface area will be , 2πrh

⇒ 2 × 22/7 × 18 × 24 = 2715.43 m2

∴ The correct option is 3