Question
Download Solution PDFWhat is the value of x for balanced chemical equation 3Fe + xH2O → Fe3O4 + 4H2?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe Correct answer is 4.
Key Points
- To balance the given chemical equation 3Fe + xH2O → Fe3O4 + 4H2, we need to ensure that the number of atoms of each element on both sides of the equation is equal.
- On the product side, Fe3O4 contains 3 iron (Fe) atoms and 4 oxygen (O) atoms. Additionally, there are 4 molecules of hydrogen gas (H2), which account for 8 hydrogen (H) atoms on the product side.
- On the reactant side, there are 3 iron (Fe) atoms provided by the 3Fe. However, to balance the 4 oxygen atoms and 8 hydrogen atoms on the product side, we require 4 water molecules (H2O), as each water molecule contains 1 oxygen atom and 2 hydrogen atoms.
- Thus, the balanced equation becomes: 3Fe + 4H2O → Fe3O4 + 4H2.
- Here, the value of x = 4, which corresponds to the number of water molecules required to balance the equation.
- This balanced equation ensures the conservation of mass, as the total number of atoms of each element is the same on both sides.
Additional Information
- Importance of Balancing Chemical Equations:
- Balancing chemical equations ensures the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction.
- It helps in determining the stoichiometric proportions of reactants and products in a reaction.
- Balanced equations are essential for calculating the quantities of reactants and products in chemical processes.
- Fe3O4 (Magnetite):
- Magnetite is a naturally occurring iron oxide mineral with a chemical formula of Fe3O4.
- It is widely used as a source of iron in the steel manufacturing industry.
- Magnetite is also known for its magnetic properties, making it useful in various industrial applications.
Last updated on Jul 16, 2025
-> The Railway RRB Technician Notification 2025 have been released under the CEN Notification - 02/2025.
-> As per the Notice, around 6238 Vacancies is announced for the Technician 2025 Recruitment.
-> A total number of 45449 Applications have been received against CEN 02/2024 Tech Gr.I & Tech Gr. III for the Ranchi Region.
-> The Online Application form for RRB Technician is open from 28th June 2025 to 28th July 2025.
-> The Pay scale for Railway RRB Technician posts ranges from Rs. 19900 - 29200.
-> Prepare for the exam with RRB Technician Previous Year Papers.
-> Candidates can go through RRB Technician Syllabus and practice for RRB Technician Mock Test.