Which of the following interchange of numbers and mathematical signs would make the given equation correct?

28 + 7 × 10 ÷ 5 - 20 = 5

This question was previously asked in
SSC CGL 2022 Tier-I Official Paper (Held On : 13 Dec 2022 Shift 1)
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  1. 10 and 20, × and +
  2. 5 and 20, - and ÷
  3. 7 and 28, × and ÷
  4. 5 and 10, + and ÷

Answer (Detailed Solution Below)

Option 4 : 5 and 10, + and ÷
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Detailed Solution

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Mistake Point

  • Please note that, in this kind of question we have to replace the digits on the right-hand side too that's why 5 is replaced by 10 in the given solution.

 

BODMAS

Given equation : 28 + 7 × 10 ÷ 5 - 20 = 5

According to the question, after interchanging of numbers and mathematical signs:

So,

  • Option - (1) : 10 and 20, × and +

28 × 7 + 20 ÷ 5 - 10 = 5

28 × 7 + 4 - 10 = 5

196 + 4 - 10 = 5

200 - 10 = 5

190 ≠ 5 (LHS ≠ RHS)

  • Option - (2) : 5 and 20, - and ÷

28 + 7 × 10 - 20 ÷ 5 = 20

28 + 7 × 10 - 4 = 20

28 + 70 - 4 = 20

98 - 4 = 20

94 ≠ 20 (LHS ≠ RHS)

  • Option - (3) : 7 and 28, × and ÷

7 + 28 ÷ 10 × 5 - 20 = 5

7 + 2.8 × 5 - 20 = 5

7 + 14 - 20 = 5

18 - 20 = 5

-2 ≠ 5 (LHS ≠ RHS)

  • Option - (4) : 5 and 10, + and ÷

28 ÷ 7 × 5 + 10 - 20 = 10

4 × 5 + 10 - 20 = 10

20 + 10 - 20 = 10

30 - 20 = 10

10 = 10 (LHS = RHS)

Hence, "Option - (4)" is the correct answer.

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