A policeman follows a thief, who is 1250 m ahead of him. The policeman and the thief run at the speed of 10 km/h and 8 km/h, respectively. The distance (in km) run by the thief before he is nabbed by the policeman is:

Question

Question

This question was previously asked in

SSC CGL 2023 Tier-I Official Paper (Held On: 14 Jul 2023 Shift 4)

Answer 1

Given:

Distance between policeman and thief in the starting = 1250 m

Speed of policeman = 10 km/hr

Speed of thief = 8 km/hr

Concept: /Formula:

If the speed of a policeman and thief is x km/hr and y km/hr, then

Relative speed, if same directions = (x – y) km/hr

Distance between them after n hrs = (x – y) × n

1 km/hr = 5/18 m/sec

1 min = 60 sec

Calculation:

Distance between policeman and thief in starting = 1250 m

Relative speed of policeman and thief, if same directions = (10 – 8) = 2 × (5/18) = (5/9) m/sec

Time is taken by a policeman to cover the gap = 1250/(5/9)

= 2250 sec

The distance (in km) run by the thief before he is nabbed by the policeman = 8 × 2250/3600

= 5 km

The distance (in km) run by the thief before he is nabbed by the policeman is 5 km.