Question
Download Solution PDFএকটি ΔABC-এ, D হল BC-এর উপর একটি বিন্দু। AB কে E পর্যন্ত এবং AC কে F পর্যন্ত প্রসারিত করা হয়েছে। একটি বৃত্ত DEF এর মধ্যে দিয়ে যায়, যেখানে AB = 10 সেমি, AC = 8.6 সেমি এবং BC = 6.4, তাহলে BE = ?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFধারণা:
একই বহিঃস্থ বিন্দু থেকে একটি বৃত্তে অঙ্কিত স্পর্শকগুলির দৈর্ঘ্য সমান হয়।
গণনা:
প্রদত্ত, AB = 10 সেমি, AC = 8.6 সেমি এবং BC = 6.4 সেমি
ধরি BE = x সেমি এবং CF = y সেমি
আমরা জানি,
BE = BD [স্পর্শক]
DC = CF [স্পর্শক]
AE = AF [স্পর্শক]
AB + BE = AC + CF
⇒ 10 + x = 8.6 + y
⇒ x - y = 8.6 - 10
⇒ x - y = - 1.4 ----(1)
BD + DC = 6.4
⇒ x + y = 6.4 ----(2)
সমীকরণ (1) এবং সমীকরণ (2) থেকে পাই,
⇒ x = 2.5
∴ BE = 2.5 সেমি
Last updated on Jul 21, 2025
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