\(\frac{20 + 20 \tan^2A}{50 + 50 \cot^2A}\) এর মান হল:

Question

Question

This question was previously asked in

RRB Group D 2 Sept 2022 Shift 2 Official Paper

Answer 1

প্রদত্ত:

\(\dfrac{20 + 20 \tan^2A}{50 + 50 \cot^2A}\)

অনুসৃত ধারণা:

\( \dfrac{sec^2}{cosec^2} \) = tan ² A

tan² A + 1 = sec ² A

cot² A + 1 = cosec ² A

গণনা :

⇒ \(\dfrac{20 + 20 \tan^2A}{50 + 50 \cot^2A}\)

⇒ \(\dfrac{2(1 + \tan^2A)}{5(1 + \cot^2A)}\)

⇒ \(\dfrac{2(\sec^2A)}{5(cosec^2A)}\)

⇒ \(\dfrac{2}{5}\tan^2A\)

∴ \(\dfrac{20 + 20 \tan^2A}{50 + 50 \cot^2A}\) = \(\dfrac{2}{5}\tan^2A\)