Question
Download Solution PDFएक विद्युत परिपथ का प्रवेश्यता को Y = (3 + j4) द्वारा दर्शाया जाता है। इस परिपथ में प्रतिरोध का मान क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
प्रतिबाधा (Z) = \({1\over Admittance (Y)}\)
Z = R + jX
जहाँ, R = प्रतिरोध और X = प्रतिघात
Y = G + jB
जहाँ, G = चालकता & B = आग्राहिता
गणना:
दिया गया है, Y = 3 + j4
\(Z={1\over 3+j4}\)
\(Z={1\over 3+j4}\times{3-j4\over 3-j4}\)
\(Z={1\over 25}(3-j4)\)
प्रतिरोध, R = \(\frac{3}{25}\Omega\)
Last updated on Jul 1, 2025
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