If 8 tan A = 5, what is the value of \(\frac{8 \sin A-7 \cos A}{8 \sin A+11 \cos A} \)?

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SSC Selection Post 2024 (Higher Secondary Level) Official Paper (Held On: 21 Jun, 2024 Shift 2)
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  1. \(\frac{-1}{8}\)
  2. \(\frac{1}{19}\)
  3. \(\frac{1}{8}\)
  4. \(\frac{-1}{6}\)

Answer (Detailed Solution Below)

Option 1 : \(\frac{-1}{8}\)
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Detailed Solution

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Given:

8 tan A = 5

Formula used:

\(\tan A = \dfrac{\sin A}{\cos A}\)

Calculation:

Given:

\(\dfrac{\sin A}{\cos A} = \dfrac{5}{8}\)

Let \(\sin A = 5k\) and \(\cos A = 8k\)

Now, substitute in the given expression:

\(\dfrac{8(5k) - 7(8k)}{8(5k) + 11(8k)}\)

\(\dfrac{40k - 56k}{40k + 88k}\)

\(\dfrac{-16k}{128k}\)

\(-\dfrac{1}{8}\)

∴ The correct answer is \(\frac{-1}{8}\).

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