Question
Download Solution PDFABC त्रिकोणामध्ये, कोन BAC चा दुभाजक D वर BC रेषा कापतो. जर BD = 6 आणि BC = 14 असेल तर AB ∶ AC चे मूल्य किती असेल?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिले:
त्रिकोण ABC मध्ये, कोन BAC चा दुभाजक D वर BC रेषा कापतो.
BD = 6 आणि BC = 14
वापरलेली संकल्पना:
कोन दुभाजक प्रमेय: त्रिकोणाचा कोन दुभाजक त्रिकोणाच्या इतर दोन बाजूंच्या प्रमाणात विरुद्ध बाजूस दोन भागांमध्ये विभागतो.
गणना:
DC = BC - BD = 14 - 6 = 8 सेमी
कोन दुभाजक प्रमेयानुसार,
BD/CD = AB/AC
⇒ 6/8 = AB/AC
⇒ AB : AC = 3 : 4
∴ AB : AC चे मूल्य 3 : 4 आहे.
Last updated on Jul 14, 2025
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