Question
Download Solution PDFThe median AD of a triangle ABC is produced and a perpendicular CF is dropped on it. BE is perpendicular to AD. If BC = 34 cm and DF = 8 cm, what is the length (in cm) of BE?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
BC = 34 cm
DF = 8 cm
Formula Used:
In a triangle, median bisects the side.
Calculation:
Given BC = 34 cm
In triangle BED and CDF
BD = CD (because AD is median)
∠E = ∠F
∠BDE = ∠CDF (vertically opposite angles)
Therefore Triangle BED and CDF are congruent
Therefore, BE = CF
In triangle BED:
(BD)2 = (BE)2 + (ED)2
⇒ (17)2 = (BE)2 + (8)2
⇒ 289 = 64 + (BE)2
⇒ (BE)2 = 289 - 64
⇒ BE = \(\sqrt(225)\)
⇒ BE = 15 cm
Thus, the length of BE is 15 cm.
Last updated on Jun 3, 2025
-> The Staff Selection Commission has officially released the SSC Selection Post Phase 13 Notification 2025 on its official website at ssc.gov.in.
-> A total number of 2423 Vacancies have been announced for various selection posts under Government of India.
-> The Computer Based Exam is scheduled from 24th July to 4th August, 2025. Candidates will be able to apply online from 2nd June 2025 to 23rd June 2025.
-> The SSC Selection Post Phase 13 exam is conducted for recruitment to posts of Matriculation, Higher Secondary, and Graduate Levels.
-> The selection process includes a CBT and Document Verification.
-> Some of the posts offered through this exam include Laboratory Assistant, Deputy Ranger, Upper Division Clerk (UDC), and more.
-> Enhance your exam preparation with the SSC Selection Post Previous Year Papers & SSC Selection Post Mock Tests for practice & revision.