Question
Download Solution PDFTwo simply supported beams with central (mid span) concentrated loads have the following particulars. Compare the slope at the ends.
| Particulars | Beam A | Beam B |
| Length of the beam | 5 m | 10 m |
| EI | EI | 2 EI |
| Value of central concentrated load | 2 kN | 1 kN |
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
In the case of the simply supported beam as shown in the figure below:
\({\delta_c} = \frac{{P{L^3}}}{{48EI}}\)
\({\theta _B} = \theta _A=\frac{{w{L^2}}}{{16EI\;}}\)
Calculation:
Slope for Beam A
\(\theta _A=\frac{{w{L^2}}}{{16EI\;}}=\frac{{2{\times5^2}}}{{16EI\;}}\) = 50/16EI
Slope for Beam B
\(\theta _B=\frac{{w{L^2}}}{{16EI\;}}=\frac{{1{\times10^2}}}{{16\times 2EI\;}}\) = 50/16EI
Hence, Slope of beam A = Slope of beam B
Last updated on Jul 1, 2025
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