What is the value of \(\frac{{1 + a}}{{{a^{1/2}} + {a^{ - 1/2}}}} - \frac{{{a^{1/2}} + {a^{ - 1/2}}}}{{1 + a}} + {a^{ - 1/2}}?\)

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SSC CGL Previous Paper 14 (Held On: 11 August 2017 Shift 2)
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  1. √a
  2. 1/√a
  3. √a + 1
  4. √a – 1

Answer (Detailed Solution Below)

Option 1 : √a
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Detailed Solution

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Given:

{[(1 + a) / (a1/2 + a-1/2) + a-1/2] – [(a1/2 + a-1/2) / (1 + a)]}

⇒ {[(1 + a) + (a1/2 + a-1/2)(a-1/2) / (a1/2 + a-1/2)] – [(a1/2 + a-1/2) / (1 + a)]}

⇒ {[(2 + a + a-1) / (a1/2 + a-1/2)] – [(a1/2 + a-1/2) / (1 + a)]}

⇒ {[(2 + a + a-1)(1 + a) – (a1/2 + a-1/2)2] / [(a1/2 + a-1/2)(1 + a)]}

⇒ {[(a2 + 3a + a-1 + 3) – (a + a-1 + 2)] / [(a1/2 + a3/2 + a-1/2 + a1/2)]}

⇒ {(a2 + 2a + 1) / (2a1/2 + a3/2 + a-1/2)}

Taking a1/2 common from the numerator

⇒ a1/2[(2a1/2 + a3/2 + a-1/2)] / [( 2a1/2 + a3/2 + a-1/2)]

⇒ a1/2 (1) = √a

∴ the correct option is 1
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