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If 27x + 27[x-(1/3)] = 99, then what is the value of x?

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SSC CGL Previous Paper 19 (Held On: 16 August 2017 Shift 1)
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Answer (Detailed Solution Below)

Option 1 : 2
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Detailed Solution

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Given: 27x + 27[x-(1/3)] = 99

Taking 9 as common, we get

⇒ 9[3x + 3x - (1)] = (9)(11)

⇒ 6x - 1 = 11

⇒ 6x = 12

∴ x = 2
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