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This article features a collection of questions and answers on the perimeter of a rectangle to assist students in mastering this topic. The perimeter of a shape refers to its outer boundary. To accelerate your understanding, we have compiled a list of questions related to the perimeter of a rectangle, complete with detailed solutions. To learn more about the concept of a rectangle's perimeter, click here .
The perimeter of a rectangle means the total distance around the outside of the rectangle. It is the length of all four sides added together.
We usually measure this in units like meters, inches, feet, or yards, because it's a straight-line distance.
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The perimeter of a rectangle is the total distance around it. To find it, we add the length and the breadth (width) of the rectangle, and then multiply the result by 2.
Formula:
Perimeter = 2 × (Length + Breadth)
Solution:
We can find the perimeter of the rectangle using its formula.
As we know,
Perimeter of rectangle = 2(length + breadth) units.
Given that, Length = 15 cm, and breadth = 10 cm.
Substituting the values in the perimeter formula, we get
Perimeter of rectangle = 2(15 + 10)
Perimeter = 2(25)
Perimeter = 50 cm.
Therefore, the perimeter of the rectangle is 50 cm.
Solution:
To find out the amount of lace required for the border of the tablecloth, we need to calculate the perimeter of the tablecloth using the rectangle's perimeter formula.
Given,
Length, l = 150 inches
Breadth, b = 120 inches.
As we know, the perimeter of a rectangle = 2(l + b) units.
Substituting the values in the formula, we get
Perimeter = 2(150 + 120) = 2 × 270 = 540 inches.
Hence, we will need 540 inches of lace to complete the border.
Solution:
Given that, Length, l = 7 cm
Breadth, b = 5 cm
The formula to calculate the perimeter of a rectangle is given as follows:
Perimeter = 2 × (Length + Breadth) units.
Substituting the values in the formula, we get
Perimeter = 2 × (7 + 5) cm
Perimeter = 2 (12) cm
Perimeter = 24 cm
Hence, the perimeter of the rectangle is 24 cm.
Solution:
Given: Perimeter = 300 m and length, l = 100 m.
To find: Breadth (b).
As we know, rectangle’s perimeter = 2 (l + b)
Substituting the given values, we derive the following:
2(l + b) = 300 m
Dividing both sides by 2, we get
l + b = 150 m
Substituting l = 100 m, we get
100 + b = 150 m
Simplifying the above equation, we get
b = 150 – 100 m
b = 50 m
Hence, the breadth of the rectangular field is 50 m.
Solution:
Given: Area of rectangular plot = 500 m 2 .
Length = 25 m.
To find : Breadth and perimeter of the rectangular plot.
As we know, Area = Length × Breadth
Substituting the given values in the formula to find the breadth, we get
500 = 25 × Breadth
Breadth = 500/25 = 20 m
Therefore, the breadth of the rectangular plot = 20 m.
Substituting the length and breadth values in the perimeter formula, we get
Perimeter = 2 (Length + Breadth) units
Perimeter = 2 (25 + 20)
Perimeter = 2 (45)
Perimeter = 90 m
Therefore, the perimeter of the rectangular plot of land is 90 m.
Further reading: Rectangle .
Solution:
From the given figure, it is observed that,
Length = 35 cm and breadth = 25 cm.
Substituting these values in the perimeter of rectangle formula, we get
Perimeter of rectangle = 2 × (length + breadth) units
Perimeter = 2 × (35 + 25)
Perimeter = 2 × 60
Perimeter = 120 cm
Therefore, the perimeter of the rectangle, if length = 35 cm and breadth = 25 cm, is 120 cm.
Solution:
Given: Perimeter of rectangle = 60 m.
Let's assume the rectangle’s breadth is y.
According to the given condition, the rectangle’s length will be 4y−6.
As we know, perimeter of rectangle = 2(length + breadth) units
Substituting the obtained values in the formula, we get
⇒ 60 = 2(4y−6+y)
Simplifying the above equation, we get
⇒ 60 = 2 (5y- 6)
⇒ 60 = 10y- 12
⇒ 10y = 60+12
⇒ 10y = 72
⇒ y = 72/10
⇒ y = 7.2
Therefore, the breadth of the rectangle = 7.2 m.
So, Length = 4(7.2) – 6
Length = 28.8 – 6
Length = 22.8
Hence, the length of the rectangle = 22.8 m.
We know that,
Area of rectangle = length × breadth square units.
Area = 22.8 × 7.2 m 2
Area = 164.16 m 2
Hence, the area of the rectangle is 164.16 m 2 .
Solution:
Let's denote the given figure as follows:
Given that, the area of one rectangle is 12m 2
Also, breadth = 3m
As we know, Area = length × breadth
Substituting the given values in the formula, we get
⇒ length × breadth = 12
⇒ length × 3 = 12
⇒ length = 4 m
Since all the four rectangles are equal, all the rectangles have a length 4 m and a breadth 3m.
The perimeter of rectangle ABCD is given by:
= AB + BC + CD + DA + AE + EF + FA
Here, small lengths represent the breadth, while longer lengths represent the length.
Therefore, perimeter of rectangle ABCD = 4 + 3 + 4 + 3 + 4 + 3 + 4 + 3 = 28m
Thus, the perimeter of the rectangle ABCD is 28 metres.
Solution:
Given that rectangle’s perimeter = 396 cm.
Also, The rectangle is divided into 6 equal rectangles.
To find: Perimeter of one rectangle.
Let's denote the figure as shown below with the letters “l” and “b”.
Assume that, length = l and breadth = b
As we know, rectangle’s perimeter = 2(length + breadth) units
From the diagram as shown above, the perimeter of a rectangle is calculated as follows:
= l + b + l + l + b + l + b + b + b
= 4l + 5b
Therefore, 396 = 4l + 5b … (1)
In addition, the figure shows that the 3 breadth of the top vertical rectangles is equal to the 2 lengths of the 2 bottom horizontal rectangles.
Hence, we can write,
2l = 3b … (2)
Substituting (2) in (1), we get
396 = 2(3b) + 5b
Simplifying the above equation, we get
396 = 6b + 5b
11b = 396
b = 396/11
b = 36 cm
Hence, breadth = 36 m
Substituting b = 36 in (2), we get
2l = 3(36)
l = 3(36)/2
l = 3(18)
l = 54 cm
Hence, length = 54 cm
Therefore, the perimeter of one rectangle = 2(54 + 36)
= 2(90)
= 180 cm
Therefore, one of the rectangles’ perimeter is 180 cm.
Solution:
The perimeter of the given track = Total distance around the track
The track consists of two semi-circular paths and a rectangular path.
Therefore, the perimeter of the given track = 62 + 62 + 2πr
Perimeter = 62 + 62 + [2(22/7)20]
Perimeter = 124+125.71
Perimeter = 249.71 ≈ 250 cm.
Hence, the total distance around the track rounded to the nearest whole centimetre is 250 cm.
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