Question
Download Solution PDFFind the weight of a cylindrical iron container with base radius 12.6 cm and height is 4 m, where the weight of 1 cm3 of iron is 2 grams?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Radius of the base (r) = 12.6 cm
Height (h) = 4 m
Weight of 1 cm³ of iron = 2 grams
Formula:
Volume (V) = πr²h
Calculation:
Convert the height from meters to centimeters:
Height (h) = 4 m × 100 cm/m = 400 cm
Now, calculate the volume of the cylindrical iron container:
V = π × (12.6 cm)² × 400 cm = 2 × 63504 cm³ = 199584 cm³
Now, calculate the weight of the iron container:
Weight = Volume × Weight per cm³
Weight = 199584 cm³ × 2 grams/cm³ = 399168grams
Convert grams to kilograms (1 kg = 1000 grams)
Weight = 399168 grams / 1000 = 399.168 kg
So, the correct weight of the cylindrical iron container is approximately 399.168 kg.
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