Question
Download Solution PDFनिम्नलिखित में से कौन सा कथन सही है?
I. यदि \(\mathrm{K}+\frac{1}{\mathrm{~K}}=12\) है, तो \(\mathrm{K}^2+\frac{1}{\mathrm{~K}^2}=142\)
II. \(\left(\mathrm{k}^2+\frac{1}{\mathrm{k}^2}\right)\left(\mathrm{k}-\frac{1}{\mathrm{k}}\right)\left(\mathrm{k}^4+\frac{1}{\mathrm{k}^4}\right)\left(\mathrm{k}+\frac{1}{\mathrm{k}}\right)\) का मान
\(\mathrm{k}^{16}-\frac{1}{\mathrm{k}^{16}}\) है।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
k + 1/k = 12
प्रयुक्त सूत्र:
(x + 1/x)2 = (x2 + 1/x2) + 2
(a - b)(a + b) = a2 - b2
गणना:
पहले कथन को लेने पर,
k + 1/k = 12
का प्रयोग करने पर
(x + 1/x)2 = (x2 + 1/x2) + 2
(k2 + 1/k2) = 144 - 2
(k2 + 1/k2) = =142
अतः, पहला कथन सत्य है।
दूसरा कथन लेने पर,
\(\left(\mathrm{k}^2+\frac{1}{\mathrm{k}^2}\right)\left(\mathrm{k}-\frac{1}{\mathrm{k}}\right)\left(\mathrm{k}^4+\frac{1}{\mathrm{k}^4}\right)\left(\mathrm{k}+\frac{1}{\mathrm{k}}\right)\)
(a - b)(a + b) = a2 - b2 का प्रयोग करने पर,
\(\left(\mathrm{k}^2+\frac{1}{\mathrm{k}^2}\right)\left(\mathrm{k^2}-\frac{1}{\mathrm{k^2}}\right)\left(\mathrm{k}^4+\frac{1}{\mathrm{k}^4}\right)\)
\(\left(\mathrm{k^4}-\frac{1}{\mathrm{k^4}}\right)\left(\mathrm{k}^4+\frac{1}{\mathrm{k}^4}\right)\)
\(\mathrm{k}^{8}-\frac{1}{\mathrm{k}^{8}}\)
अतः, दूसरा कथन सत्य नहीं है।
इसलिए केवल कथन I सत्य है।
∴ विकल्प 1 सही उत्तर है।
Mistake Points
कृपया ध्यान दीजिए कि,
(K4)2 = K4 * 2 = K8
अतः कथन 2 सही नहीं है।
Last updated on Jul 14, 2025
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