Question
Download Solution PDFIn the figure given below, SPT is a tangent to the circle at P and O is the centre of the circle. If ∠QPT = α, then what is ∠ POQ equal to?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDF∠OPT = 90° [∵ Radius is perpendicular to tangent]
∠OPQ = 90° - ∠QPT = 90° - α
∠OQP = 90° - α [∵ OQ = OP]
In triangle OQP
∠O + ∠Q + ∠P = 180°
∠O + 90 - α + 90 - α = 180
∴ ∠O = 2α
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