Question
Download Solution PDFखालील आकृतीत, SPT ही वर्तुळाच्या P बिंदूवरील स्पर्शिका असून O हा वर्तुळाचा केंद्रबिंदू आहे. जर ∠QPT = α असेल, तर ∠POQ किती असेल?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDF∠OPT = 90° [∵ त्रिज्या स्पर्शिकेला लंब आहे]
∠OPQ = 90° - ∠QPT = 90° - α
∠OQP = 90° - α [∵ OQ = OP]
त्रिकोण OQP मध्ये,
∠O + ∠Q + ∠P = 180°
∠O + 90 - α + 90 - α = 180
∴ ∠O = 2α
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