Question
Download Solution PDFPAQ ही बिंदू O असलेल्या एका वर्तुळाची स्पर्शिक आहे. AB ही एक जीवा आहे जी ∠BAQ = x° (x < 90°) आहे. C हा मुख्य परिघाचा भाग असलेल्या AB वर एक बिंदू आहे जो ∠ACB = y° आहे. जर ∠ABO = 32° असेल तर x + y चे मूल्य किती?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDF∠ABO = 32°, ∠BAQ = X and ∠ACB = Y
∠ABO = ∠BAO = 32° [OA = OB]
∠OAQ = 90° [स्पर्शीका]
∠OAQ = ∠BAO + ∠BAQ
⇒ 90° = 32° + x
⇒ x = 90° - 32° = 58°
जसे आपल्याला माहित आहे,
x = y = 58°
⇒ x + y = 58° + 58°
⇒ x + y = 116°
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